
David W. answered 06/02/15
Tutor
4.7
(90)
Experienced Prof
My siblings and I made a rule: Whoever cuts the cake (pizza, pie, …) into “equal” pieces gets the last piece.
Perhaps this problem should say “unequal” parts, let them be G (greater) and S (smaller).
The problem states:
(1/8)*G = (1/2)*S [because “of” usually means multiply]
S + G = 50
Let’s use the elimination method:
G – 4*S = 0 (first equation)
G + S = 50 (second equation)
--------------------- (subtract)
0 -5*S = -50
S = 10
Then,
G + S = 50
G + 10 = 50
G = 40
Checking:
Is (1/8)*40 = (1/2)*10 ?
5 = 5 ? Yes.
Perhaps this problem should say “unequal” parts, let them be G (greater) and S (smaller).
The problem states:
(1/8)*G = (1/2)*S [because “of” usually means multiply]
S + G = 50
Let’s use the elimination method:
G – 4*S = 0 (first equation)
G + S = 50 (second equation)
--------------------- (subtract)
0 -5*S = -50
S = 10
Then,
G + S = 50
G + 10 = 50
G = 40
Checking:
Is (1/8)*40 = (1/2)*10 ?
5 = 5 ? Yes.