How likely is that the Good guys will get to play at least 2 of 5 games?

Question

The Good Guys have a series of 5 games to play, with 1 game each day from Monday to Friday.If it rains on the day of the scheduled game, the game is cancelled. There is a 30% probability of rain each day.How likely is it that the Good Guys will get to play at least 2 of 5 games? Explain.

Answer 1

Angelina,

 

this is achieved in a similar manner to your previous question except it is quicker to

calculate the result as 1-(probability no games are played + probability 1 game is played)

 

P(0,5)=(5!/(0!*5!))*(0.3)^5=(0.3)^5

P(1,5)=(5!/(1!*4!))*(0.3)^4*(0.7)^1=3.5*(0.3)^4

 

1-(P(0,5)+P(1,5))=1-(0.3+3.5)*(0.3)^4

=1-(3.8)(.0081)=0.969 (3sig. fig.)

 

(So there's about 97 pct chance the Good Guys will get to play at least 2 games).