Edward C. answered 05/15/15
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This is a binomial distribution B(n,p) with parameters n = 4 tests and p = 4/5 probability of scoring above 90
The probability of getting exactly k successes out of n trials is given by
P(X=k) = nCk * pk * (1-p)n-k
where nCk is the binomial coefficient = n!/(k!(n-k)!)
Plug in 3 for k, 4 for n, and 4/5 for p