Find equation of the line given the coordinate

Question

less students are graduating in less than 5yr. in 1983 the coordinates rep. a line of students graduating in less than 5yrs were (0,58) x rep. yr in 1983 and y rep. percent of students graduating In less than 5y. Next coordiNate is 14yr later, 1997 as (14,53). Find equation of line given the coordinate. 

Answer 1

First, use those two points to find the slope of the line. Remember that slope is rise/run, or change in y over change in x:

 

slope = (x₂ - x₁) / (y₂ - y₁) = (14 - 0) / (53 - 58) = 14/(-5) = -14/5

 

 

Now, we'll write an equation of the line in point-slope form. Point slope form is:

 

y - y₁ = m(x - x₁),

 

where m is slope and (x₁, y₁) is a point on the line. Plug in m = -14/5 and (x₁, y₁) = (0, 58):

 

y - 58 = -14/5(x - 0)

y - 58 = -14/5x

 

In slope-intercept form, that's:

 

y = -14/5x + 58