Stephanie M. answered 04/29/15
Tutor
5.0
(961)
Private Tutor - English, Mathematics, and Study Skills
For this type of problem, it's useful to make a table. Say x = the amount invested at 12%, which means that 1400 - x = the amount invested at 6% (we want them to add up to $1400 together). The first row in the table will represent the 11% stock, the second will represent the 12% stock, the third will represent the 6% stock, and the fourth will represent the overall investment:
INVESTMENT INTEREST RATE INTEREST ANNUALLY
300 0.11 0.11(300)
x 0.12 0.12x
1400 - x 0.06 0.06(1400 - x)
1700 0.09 0.09(1700)
We want the annual interest from the first three rows to equal the interest target of the final investment. So, we can set up an equation and solve for x:
0.11(300) + 0.12x + 0.06(1400 - x) = 0.09(1700)
33 + 0.12x + 84 - 0.06x = 153
117 + 0.06x = 153
0.06x = 36
x = 600
So, x = $600 should be invested in the 12% stock and 1400 - 600 = $800 should be invested in the 6% stock.