Stephanie M. answered 04/29/15
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To reflect across y = 2, we need all these points' reflections to have the same x-coordinates, but their y-coordinates must be on the other side of the horizontal line y = 2 and equally far from it. For example, (3, 4), which is 2 units above y = 2, needs to become (3, 0), which is 2 units below y = 2.
So, do this:
J'(1, 2 + (2 - 3))
This finds the distance from the point to y = 2 by subtracting the point's y-coordinate from 2, then moves the point that far to the other side of y = 2 by adding 2.
J(1, 3) = J'(1, 2 + (2 - 3)) = J'(1, 2 - 1) = J'(1, 1)
U(0, 5) = U'(0, 2 + (2 - 5)) = U'(0, 2 - 3) = U'(0, -1)
R(1, 5) = R'(1, 2 + (2 - 5)) = R'(1, 2 - 3) = R'(1, -1)
C(3, 2) = C'(3, 2 + (2 - 2)) = C'(3, 2 + 0) = C'(3, 2)
Plot those points to make sure they haven't shifted horizontally, but have reflected across the line y = 2.