Math problem

Question

Solve by factoring: 12x^2+13x+3=0

Answer 1

12x² + 13x + 3 = 0

 

(4x + 3)(3x + 1) = 0

 

 

Set these factor equal to zero.

 

4x + 3 = 0        and         3x + 1 - 0

 

4x = -3             and         3x = -1

 

x = -3/4            and          x = -1/3

 

 

The solutions are

 

x = -3/4

x = -1/3

Answer 2

12x^2+13x+3=0

12*3=2*2*3*3=(2*2)*(3*3) and 4+9=13

(4x    )(3x    )=0 so far...

(4x   3)(3x   1)=0 so far...

(4x+3)(3x+1)=0

4x+3=0

4x=-3

x=-3/4

3x+1=0

3x=-1

x=-1/3