what is 1/2x^2+10x-10 in standard form?

Question

1/2^2+10x-10 in f(x)=1/2(x^2+x)+x form? 

Answer 1

The standard form of a quadratic equation is in y=ax²+ bx + c  form, where a, b, and c are coefficients.

 

The value of a is a whole number.

 

y = (1/2)x² + 10x - 10

 

 

In standard form, the  x⁰  term, or constant term, is isolated on the right side of the equation.  Subtract (1/2)x² and subtract 10 on both sides of equation.

 

-(1/2)x² - 10x + y = -10

 

 

Multiply both sides of equation by -2.

 

x² + 20x - 2y = 20

 

 

 

I hope this help.