A city park is shaped like a right triangle with length of one leg twice the length of the other leg the area is 2500m2 what arethe the lengths of its legs

Question

I have homework over quadratic word problems but I don't know how to work them can anyone help

Answer 1

Let X be the length of the other leg  

Then 2*X is the length of the first leg  

 

In any triangle the Area is equal to (1/2)*Base*Height 

In a right triangle one leg is the Base and the other is the Height so 

 

2500 = (1/2)*(2*X)*X 

5000 = 2*X^2

X^2 = 2500

X = +50  since a length cannot be negative 

 

So one leg is 100m and  the other leg is 50 m  

 

Check:  (1/2)*50*100 = 25*100 = 2500 m^2