Jon P. answered 04/16/15
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First remember the basic rules:
logn ab = logn a + logn b
logn a/b = logn a - logn b
logn ab = b logn a
These rules apply no matter what the base of the logarithm is.
1. log6 ((2x3)/3) =
log6 (2x3) - log6 3 =
log6 2 + log6 x3 - log6 3 =
log6 2 - 3 log6 x - log6 3
2. ln (x2 y) =
ln x2 + ln y =
2 ln x + ln y
3. log7 (sqrt xy3)
It's not clear if you mean sqrt (xy3) or sqrt (x) y3. Let's guess that you meant sqrt (xy3).
So that's log7 (xy3)1/2 =
1/2 log7 (xy3) =
1/2 (log7 x + log7 (y3) =
1/2 (log7 x + 3 log7 y) =
(log7 x + 3 log7 y) / 2