Philip P. answered • 04/15/15

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The force due to a stretched spring is F = kx, where k is a constant and x is the amount of stretch. The potential, P, is:

P = k∫x dx = (1/2)kx

^{2}When x = 2, P = V:

V = (1/2) k 2

^{2}V = 2k

**V/2 = k**

So P = (1/2)(V/2)x

^{2}= (V/4)x^{2}. For x = 10 cm:P = (V/4)(10

^{2}) = 100V/4 = 25V