Mark H. answered 04/08/15
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In either case, the choices are multiplied to get the final answer.
If each student has 8 choices, then there are 8^6 = 262,144 possible combinations. Each choice is an independent event, and does not depend on any other choice.
In the first case, each student after the first has fewer choices available---i.e. the 1st student has 8 possibilities, the 2nd student has 7, etc.
With 6 students, there are 6 terms:
8 x 7 x 6 x 5 x 4 x 3 = 20,160
To be rigorous, we would say that there are 8! possible choices, but that the last two are not taken. Thus we have 8! / 2! (the answer is the same.)