07/30/23
Wt% Question for NaC2O4
Hello I am struggling to calculate the weight percentage for NaC2O4 inn a precipitate.the molarity of KMnO4 is 0.0290Mvolume of Kmno4 = 25.90mL and molarity of KMnO4 is 0.02153the mass of unknown...
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07/29/23
help with chem problem
A 0.52970.5297 g mixture of KCNKCN (MW=65.116 g/molMW=65.116 g/mol) and NaCNNaCN (MW=49.005 g/molMW=49.005 g/mol) was dissolved in water. AgNO3AgNO3 was added to the solution, precipitating all of...
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07/29/23
Analytical Chemistry Q: calculating molarity
Excess (NH4)2SO4= was added to a 55.0 mL solution containing BaCl2 (MW=208.23 g/mol). The resulting BaSO4BaSO4 (MW=233.43 g/mol) precipitate had a mass of 0.2319 g after it was filtered and dried....
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07/29/23
Ksp Questions from generic salt
A generic salt, AB, has a molar mass of 155 g/mol and a solubility of 7.40 g/L at 25 °C.AB(s) =" At (ag) + B- (aq)What is the Ksp of this salt at 25 °C?
07/29/23
I don't understand this Rydberg Equation Question
I found this question in my textbook.The hydrogen atom emits a photon with a 486 nm wavelength, corresponding to an electron decaying from the n = 4 level to which level?I first calculated...
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07/28/23
The reaction between lead ion and chloride ion is given below:
The reaction between lead ion and chloride ion is given below: Pb2+(aq) + 2 Cl-(aq) PbCl2(s) We therefore know that which of the following reactions can also occur? Pb(s) + Cl2(g) ...
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07/28/23
For the reaction 2H2O --> 2H2 + O2, which is the value of delta S
None of the aboveundeterminednegativezeropositive
07/27/23
Ka for the acid
Enough of a monoprotic weak acid is dissolved in water to produce a 0.01850.0185 M solution. The pH of the resulting solution is 2.342.34. Calculate the Ka for the acid.I keep getting 0.00113
07/27/23
Calculate Ka for the acid
Enough of a monoprotic acid is dissolved in water to produce a 1.821.82 M solution. The pH of the resulting solution is 2.972.97. Calculate the Ka for the acid.
07/26/23
Which of the following forms a solution with a pH of 13.7?
Answer choices0.02M solution of NaOH None of the above 0.5M solution of NaOH 0.04M solution of Mg(OH)2 0.5M solution of HClO4
07/26/23
Calculate the pH of a 0.035 M sulfuric acid solution
Answer choices: None of the above1.890.891.151.46
07/26/23
Half life mass of sample
Lead-210 has a half life of 20.4 years. What mass of a 2.00 g sample of Lead-210 will remain after 61.2 years?
07/24/23
Hess's Law Problem #6
What is the enthalpy for the reaction: C2H4 + H2 --> C2H6 given the following equations:C2H4(g) + 3O2(g) --> 2CO2(g) + 2H2O(l) = -1401kJ/moleC2H6(g) + 7/2O2(g) --> 2CO2(g) + H2O(l)...
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07/24/23
Hess's Laws Problem
Given the following equations:N2(g) + O2(g) --> 2NO(g) = +190.0kjN2(g) +3H2(g) --> 2NH3(g) = -91.8kj2H2(g) + O2(g) --> 2H2O(g) = -483.7kjCalculate the enthalpy for the reaction:4NH3(g) +...
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07/24/23
Hess's Law Problem
Given:SO2 + 1/2O2 ---> SO3 = Delta H of +89.5kJS + 3/2O2 -----> SO3 = Delta H of -204.2kjCalculate the Delta H for the reaction:S + O2 ---> SO2
07/22/23
An overall 1st order reaction has a rate constant of 1.8 x 10^-3 1/s. How long will it take for the reaction to be 30% complete?
Answer choices: 240 s198 s 1730 s 129 s None of the above
07/22/23
Given the rate constant to be 2.3E-4 s^-1 AT 40 degrees C and activation energy to be 62 kj/mol, at what temperature will the rate constant be 3.8E-2?
Answer choices: 831 KNone of the above398 KNone of the above125 K
07/22/23
At a certain temperature, Kc is 7.98 x 10 -2 for the equilibrium: 2 A (g)--> B (g) + C (g). What are the concentrations of B(g) and C (g) in equilibrium with 0.0566 moles/liter of A(g) ?
1.60 x 10 ^-2 M3.20 x 10^-3 M1.28 x 10^-4 MNone of the above2.56 x 10^-4 M
07/21/23
A zeroth order reaction A = B has [A]0 = 0.52 M. After 3.0 min, [A]t = .0015M. What is the rate constant in units of Ms-1?
k = 2.88 E-3 M/s None of the above k = -2.88 E-3 M/s k = 9.60 E-4 M/s k = - 9.60 E-4 M/s
07/21/23
A zeroth order reaction A = B has [A]0 = 0.012 M. After 5.0 min, [A] = .008M. What is the rate constant in units of Ms-1?
Answer choices: None of the abovek = -1.3 E-5 M/s k = - 8.0 E-4 M/s k = 1.3 E-5 M/s k = 8.0 E-4 M/s
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