Please solve! (Three 'x' to the fourth power, 'y' to the fifth power) to the power of negative three
Whenever you have a negative exponent, that means that you have to consider the "multiplicative inverse" of the base for that power. It is also considered the "flip" of the base, as the denominator is then cubed. Since there are parenthesis around the whole expression, the whole expression will invert to the bottom of your fraction, with 1 left alone in the numerator. The last step would be to cube that whole expression in the denominator. Don't forget to cube that coefficient of 3 as you multiply the powers with their corresponding variables.
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