Inactive Tutor answered 04/10/13
To solve this equation, manipulate the numbers so that the base numbers are the same. Since 4 = 2^2 we can rewrite this as:
2^3x = (2^2)^(x+2)
Expanding the exponent gives:
2^3x = 2^(2x+4)
Now that both bases are the same, we see that
3x = 2x+4
Solving for x, we subtract 2x from both sides to get
x = 4
You can plug in the value of 4 for x in the original equation and see that it is correct.