IM 3 solving systems of 3 equations

Answer 1

4x + 2y + 3z = 12

2x - 3y + 5z = -7

6x - y + 4z = -3

Switch the first and second equations:

2x - 3y + 5z = -7

4x + 2y + 3z = 12

6x - y + 4z = -3

Multiply the first equation by -2 and add to the second. Multiply the first equation by -3 and add to the third:

2x - 3y + 5z = -7

8y - 7z = 26

8y - 11z= 18

Subtract the third equation from the second:

2x - 3y + 5z = -7

8y - 7z = 26

4z = 8

So, z = 2

8y - 7(2) = 26

8y = 40

y = 5

2x - 3(5) + 5(2) = -7

2x = -2

x = -1

Solution (-1, 5, 2)

Answer 2