
Yefim S. answered 04/20/24
Math Tutor with Experience
P(t) = 3600·0.9t; P(6) = 3600·9.96 = $1913.19
Victoria G.
asked 04/20/24Yefim S. answered 04/20/24
Math Tutor with Experience
P(t) = 3600·0.9t; P(6) = 3600·9.96 = $1913.19
As Yefim was saying, if the computer is losing 10% of its value every year, we could say that it's only 90% of its old value in each new year. So you're simply multiplying by that "0.9" 6 times (i.e. 0.96). This is what is giving you the final depreciated value of $1913.19.
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