A parabola can be drawn given a focus of left bracket, 5, comma, 6, right bracket(5,6) and a directrix of y, equals, minus, 10y=−10. What can be said about the parabola?

Answer 1

y = a(x-h)2 + k If a > 0, opens up If a > 0,Vertex: (h, k)

Vertex: (h, k)

Focu s: (h, k+p)

Directrix: y = k-p

Axis of Symmetry: x = h

a = 1 / 4p

p = 1 / 4a

Use this to describe the parabola.