Inactive Tutor answered 04/09/24
Tutor
New to Wyzant
4(3x-1) = 42x+3
3x-1 = 42x+2
log 3x-1 = log 42x+2
(x - 1) log 3 = (2x + 2) log 4
Can you substitute values and solve for x?
Az A.
asked 04/09/244 * 3x-1 = 42x+3
Inactive Tutor answered 04/09/24
4(3x-1) = 42x+3
3x-1 = 42x+2
log 3x-1 = log 42x+2
(x - 1) log 3 = (2x + 2) log 4
Can you substitute values and solve for x?
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Az A.
On step 2, where did the 4 go?04/09/24