This question is well answered above! Just to write out that last step explicitly, check for extraneous solutions by plugging your solutions back into the original equation:
√(56 - (-8)) ≟ -8
√(64) ≟ -8
8 ≠ -8
√(56 - 7) ≟ 7
√(49) ≟ 7
7 = 7
Zun K.
asked 01/20/24This question is well answered above! Just to write out that last step explicitly, check for extraneous solutions by plugging your solutions back into the original equation:
√(56 - (-8)) ≟ -8
√(64) ≟ -8
8 ≠ -8
√(56 - 7) ≟ 7
√(49) ≟ 7
7 = 7
Mark M. answered 01/20/24
Retired college math professor. Extensive tutoring experience.
√(56 - x) = x
56 - x = x2
x2 + x - 56 = 0
(x + 8)(x - 7) = 0
x = 7 or -8 (-8 is extraneous)
Solution: 7
Mark M. answered 01/20/24
Mathematics Teacher - NCLB Highly Qualified
Square both sides
Set equation to zero.
Solve using factoring and Zero Product Rule
Check for extraneous roots.
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