how many imaginary roots does the following polynomial function have?

Question

p(x) = (x² - 5) (x² +4) (x² +10) (2x+6)

Answer 1

If x²+10 = 0, then x² = -10. So, x = ±√(-10) = ±√10 i

If x²+4 = 0, then x² = -4. So, x = ±√(-4) = ±2i

The other factors have only real roots.

So, there are 4 imaginary roots.

Answer 2

At least four.