The directrix of the parabola 12(y+3) = (x-4)^2 has the equation y= -6.

Question

How to find the coordinates of the focus of the parabola

Answer 1

y = a(x - h)² + k

Vertex: (h, k)

Focus: (h + k)

Directrix y = h - p

a = 1 / 4 p

Can you substitute given data and answer?