Mark M. answered 01/20/24
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Retired college math professor. Extensive tutoring experience.
3p / (p-5) - 2 / (p+3) = p / (p+3)
Multiply both sides by the LCD, (p-5)(p+3), to get:
3p(p+3) - 2(p-5) = p(p-5)
3p2 + 9p - 2p + 10 = p2 - 5p
2p2 + 12p + 10 = 0
p2 + 6p + 5 = 0
(p + 5)(p + 1) = 0
p = -1 or -5