200 = 100*[1+ (0.07/2)]2t
200/100 = 2 = [1+ (0.07/2)]2t = [1 +0.035]2t
log 1.035 (2) = log 1.035 [1 +0.035]2t = 2t
2t = log 1.035 (2)
t = [log 1.035 (2)] / 2 = { [log (2)] / [log(1.035)] } / 2
t = 10.074 years
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆
200 = 100 * e0.07t
200/100 = 2 = e0.07t
ln(2) = 0.07t
t = ln(2) / 0.07
t = 9.902 years