10,000*e0.119*2 = $12,687.09
Yes.
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆
10,000*(1 + (r/n))tn = 10,000*(1 + (0.12/4))2*4
= $12,667.70
The first loan deal is slightly better than this one.
Cadence L.
asked 11/09/234) Jim places $10,000 in a bank account that pays 11.9% compounded continuously. After 2 years, will he have enough money to buy a car that costs $12,677? If another bank will pay Jim 12% compounded quarterly, is this a better deal?
10,000*e0.119*2 = $12,687.09
Yes.
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆
10,000*(1 + (r/n))tn = 10,000*(1 + (0.12/4))2*4
= $12,667.70
The first loan deal is slightly better than this one.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.