(a) q = K + L, given that K = 1, and q = 10,
then L = q - K = 10 -1 = 9
(b) q = min {20K, 10L}, when q = 10,
In this production function, the quantity (q) is the minimum value between 20 times the capital (K) and 10 times the labor (L) inputs.
10 = min { 20*1, 10*L}
10 = min { 20, 10L}
We need the minimum value of 20 and 10L equal to 10 to minimize costs.
Since 20 is greater than 10, the minimum value will be 10L.
Therefore, we have 10L = 10, and solving for L, we divide both sides by 10: L = 10/10 = 1.
The amount of labor that minimizes costs is 1.
(c) q = min {20K, 10L}, when q = 40,
In this production function, the quantity (q) is the minimum value between 20 times the capital (K) and 10 times the labor (L) inputs.
40 = min { 20*1, 10*L}
40 = min { 20, 10L}
We need the minimum value of 20 and 10L equal to 40 to minimize costs.
Since 20 is less than 10, the minimum value will be 20.
Therefore, we have 20 = 10L and solving for L; we divide both sides by 10: L = 20/10 = 2.
The amount of labor that minimizes costs is 2.
(d) q = K0.5L0.5, when q = 10,
10 = K0.5L0.5 = 10.5L0.5
10 = L0.5
L = 102 = 100
I hope this is helpful.