Edward C. answered 03/30/15
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Caltech Grad for math tutoring: Algebra through Calculus
Let X = length of front and back of rectangle
Let Y = length of sides of rectangle
Total cost = Side + Side + Back + Front
= 10*Y + 10*Y + 10*X + 15*(X-5)
= 20*Y + 25*X - 75
Area = 4500 ==> XY = 4500 ==> Y = 4500/X
C(X) = 20*(4500/X) + 25*X - 75 = 25*X -75 + 90000*X-1
C'(X) = 25 - 90000*X-2 = 25 - 90000/X2
C'(X) = 0 when 90000/X2 = 25
X2 = 90000/25 = 3600
X = +√3600 = 60
C''(X) = 180000/X3
C''(60) > 0 so X = 60 is a minimum
Y = 4500/X = 4500/60 = 75
The garden should be 60 ft in the front and back and 75 ft on the sides