Answer for a question below

Question

What volume in milliliters of CO gas would be produced by the complete reaction of 2.40 g of C solid at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP.

Answer 1

You didn't supply the equation for the reaction, so we'll assume it to be

2C + O₂ ==> 2CO

moles of C present = 2.40 g x 1 mol C / 12 g = 0.20 mols C

moles CO produced = 0.20 mol C x 2 mol CO / 2 mol C = 0.20 mol CO

At STP, 1 mole of any ideal gas = 22.4 L

Assuming CO acts as an ideal gas, we have ...

0.20 mol CO x 22.4 L / mol = 4.48 L CO