Inactive Tutor answered 03/24/15
Bassant Z.
asked 11/07/13Resonance Contributor
3 Answers By Expert Tutors
Inactive Tutor answered 11/07/13
Resonance structures are not something you guess at — there is a short procedure, and only three legal moves. Once you know the three moves it becomes mechanical.
The one rule that governs everything: only electrons move. Never atoms. If your second structure has a hydrogen or a carbon in a different place, you have drawn a different molecule (an isomer), not a resonance contributor. Every contributor must have identical atom connectivity and the same total charge.
The only three moves
1. Lone pair → adjacent bond. A lone pair on an atom next to a positive center or next to a pi bond folds down to become a pi bond.
2. Pi bond → adjacent bond. A pi bond shifts one position over — this is what walks charge around a conjugated system or a benzene ring.
3. Pi bond → lone pair. A pi bond collapses onto one of its two atoms, giving that atom a lone pair and a negative charge, and leaving the other atom positive.
That is the whole toolkit. Arrows start at electrons (a lone pair or the middle of a pi bond) and point to where those electrons end up.
The procedure
Draw the Lewis structure with all lone pairs shown. Find a p orbital or lone pair sitting adjacent to a pi bond, a positive charge, or a radical — adjacency is the requirement, because the orbitals must overlap. Push one arrow. Redraw the whole structure. Recount formal charges on every atom you touched. Repeat until no legal move remains.
Ranking them — this is what exam questions actually ask
Best to worst: (1) every atom has a full octet; (2) the fewest formal charges; (3) negative charge on the most electronegative atom, positive charge on the least; (4) no like charges adjacent to each other.
Rule 1 usually beats rule 3 when they conflict. A structure with a complete octet and a charge on carbon typically contributes more than one with an incomplete octet and a charge on oxygen.
What the arrow between structures means. The double-headed arrow (↔) is not an equilibrium. The molecule is not flickering back and forth. The real electron distribution is a single unchanging hybrid, and the contributors are just the best drawings our notation can manage — weighted by that ranking list. The lowest-energy contributor looks most like reality.
The mistakes that cost the most points: breaking a sigma bond (only pi electrons and lone pairs move); exceeding an octet on a second-row atom — C, N, O, and F can never hold more than 8 electrons; forgetting to update formal charge after pushing an arrow; and using ↔ when you meant ⇌.
Practice on the acetate ion, the allyl cation, and nitrobenzene, in that order. Those three cover all three moves.
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Robert S.
08/02/21