When solving 8 adult tickets and 5 students tickets and only 620 are allowed how do we solve that

Question

When solving 8 adult tickets and 5 students tickets and only 620 are allowed how do we solve that?

8a+5s=620

Answer 1

To solve the problem of purchasing adult and student tickets where you can only buy a total of 620 tickets, you can set up a system of equations to represent the situation. Let's use

A for the number of adult tickets and S for the number of student tickets.

The problem can be represented with the following equations:

The total number of tickets must not exceed 620:

A+S≤620

The total cost of adult tickets and student tickets should match a certain budget, but you'll need more information to set up this equation. If you have the cost of each type of ticket, you can set up an equation based on the total cost.

Without the specific cost information, you can use the first equation to represent the number of tickets. To find the maximum combination of tickets within the budget . To find the specific number of adult and student tickets, you would need additional information about the cost of each type of ticket.

Answer 2

There seems to be missing information in your question (like the total price).

I think you might be saying that adult tickets are $8 each and student tickets are $5 each and there are a total of 620 tickets sold.

You can define "a" as the number of adult tickets sold and "s" as the number of student tickets sold.

Then a + s = 620

You can also write a statement about what the prices are. The total price of all the adult tickets would be the cost of one adult ticket multiplied by the number of adult tickets sold or "8a" and the total price of all the student tickets would be "5s". So the total price of all tickets would be "8a + 5s". If you are given that the total price is some number, you could say:

8a + 5s = (some number)

Then you would have two equation in 2 unknowns and you could solve be several methods, including substitution. To do that, start with the first equation "a + s = 620" and solve for either "a" or "s" (a = 620 - s or s = 620 - a) then you can substitute into the other equation (wherever the 2nd equation has "a", you can insert "620 - s" in its place, or wherever the 2nd equation has "s", you can insert "620 - a" in its place). You get to choose what you want to substitute.

Then solve. Once you solve one variable, you plug the result into a + s = 620 to solve for the other variable.