which function has a y-intercept at (0,3)

Answer 1

Which function has a y-intercept at (0,3)?

I agree there was probably supposed to be a group of graphs or list of equations to choose from.

In the absence of this, here's a small list of functions that have a y-intercept at (0,3).

Linear: f(x) = mx + 3, for any slope m

Quadratic: f(x) = ax² + bx + 3, for any coefficients a and b

n^th order Polynomial: f(x) = a_nxⁿ + a_n-1x^n-1 + ... + a₁x + 3, for any coefficients a₁–a_n

Square root: f(x) = √x + 3

Trig function: f(x) = sin(x) + 3, f(x) = cos(x) + 2, or f(x) = 3cos(x)

Exponential: f(x) = e^x + 2 or f(x) = b^x + 2 for any b ≠ 0

Natural Logarithm: f(x) = ln(x +1) + 3

Answer 2

If there are supposed to be graphs pictured, then it is the graph that crosses the vertical (y) axis at y = 3 (as mentioned above).

Answer 3

I cannot see the functions in this problem, but I can tell you that when you put 0 in for x and solve for y, if you get y = 3 for an answer, then yes, it has a y-intercept of (0,3). Otherwise, no.