(-128p^-3/2)-1 solve when p=16 and p=64

Answer 1

First, note that P^-3/2 = 1/P^3/2. You can evaluate this on a scientific calculator by first evaluating P^3/2 and inverting the result. After that its standard algebra.

For P = 16:

P ^3/2 = 64

1/P = 0.015625

(-128 x 0.015625) -1 = -3

Try it with P = 64

I am assuming solve means to evaluate the expression.

Answer 2

(-128p^-3/2)-1 when p=16

= (-128(16)^-3/2)-1

= (-128/64)-1

=-2^-1

= -1/2 if that -1 was intended as an exponent

or

=-3 if you meant subtraction, minus 1 as another term, not an exponent

if p=64,then p^-3/2 = 1/psqrp = 1/64(8)=1/512

-128/512 =-1/4

-1/4 to the -1 power = -4

or if you mean -1 as subtraction not a power then

=-5/4

the problem is possibly ambiguous as written