William C. answered 09/21/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
The number of noncommercial orbital launches was three more than three times the number of commercial orbital launches. This means
N = 3C + 3 (where N = noncommercial launches and C = commercial launches)
N + C = 47 is the total number of commercial and noncommercial launches
Solving for C (number of commercial launches)
Replace N with 3C + 3 in the second equation and solve for C
3C + 3 + C = 47 which means that
4C + 3 = 47
Subtract 3 from both sides to get
4C = 44
Divide both sides by 4 to get
C = 44/4 =
Solving for N (number of noncommercial launches)
N + C = 47 means that
N = 47 – C =
Plug in the value of C you solved for above and you have your value for N