
Mike D. answered 09/03/23
Effective, patient, empathic, math and science tutor
Suppose the amount after n years is A(n), and he deposits $ 5500 at time zero.
Then A(0) = 5500 and we need A(15)
To find A(n+1) multiply A(n) by 1.085 (adds 8.5% interest per year) and add 5500
So A(0) = 5500
A(n+1) = 1.085 A(n) + 5500
A(1) = 1.085 X 5500 + 5500 = 11467.50
A(2) = 11467.50 x 1.085 + 5500 = 17942.24
etc.
In theory you can work forward to A(15) however you are likely to get some small rounding errors coming in.
The general result is a(n) = (p^n) a(0) + r (1- p^n) / (1 - p)
a(0) = 5500, n = 15, p = 1.085, r = 5500