Inactive Tutor answered 08/11/23
Let x be the amount of the 10% solution to add to the 80ml of 3% solution to make 8% of the total solution.
0.03(80) + 0.10x = 0.08(x+80)
2.4 + 0.1x = 0.08x+6.4
0.02x = 4
x= 200 ml
Ghost K.
asked 08/11/23A pharmacist wishes to mix a solution that is 8% Minoxidil. She has on hand 80ml of a 3% solution and wishes to add some 10% solution to obtain the desired 8% solution. How much 10% solution should she add?
Inactive Tutor answered 08/11/23
Let x be the amount of the 10% solution to add to the 80ml of 3% solution to make 8% of the total solution.
0.03(80) + 0.10x = 0.08(x+80)
2.4 + 0.1x = 0.08x+6.4
0.02x = 4
x= 200 ml
Inactive Tutor answered 08/11/23
80(.03) + .10x = .08(80+x)
2.4 -6.4 = .08x -.1x
4= .02x
x = 4/.02 = 200 mL of 10%
mixed with 80 mL 3%
yields 280 mL 8%
10-8=2
8-3 =5
5/2 = 2 1/2 times as much 10% as 3%
x/80 = 2.5
x = 200 mL 10%
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Ghost K.
Thank You08/11/23