(Count occurrence of numbers)

Question

Write a program that reads some integers between 1 and 100 and counts the occurrences of each. Note that if a number occurs more than one time, the plural word “times” is used in the output. Note the integers are entered in one line separated by a space. Also note that the numbers are displayed in increasing order.

Sample Run

Enter integers between 1 and 100, inclusive: 2 5 6 5 4 3 23 43 2

2 occurs 2 times

3 occurs 1 time

4 occurs 1 time

5 occurs 2 times

6 occurs 1 time

23 occurs 1 time

43 occurs 1 time

Answer 1

def count_occurrences(numbers):

occurrences = {}

for num in numbers:

occurrences[num] = occurrences.get(num, 0) + 1

sorted_occurrences = sorted(occurrences.items())

for num, count in sorted_occurrences:

times = "time" if count == 1 else "times"

print(f"{num} occurs {count} {times}")

if __name__ == "__main__":

try:

input_string = input("Enter integers between 1 and 100, inclusive: ")

numbers = list(map(int, input_string.split()))

valid_numbers = [num for num in numbers if 1 <= num <= 100]

count_occurrences(valid_numbers)

except ValueError:

print("Invalid input. Please enter integers between 1 and 100, separated by a space.")