write the equation of the line in point slope form

Question

Write the equation of the line in Point-Slope Form given the information below.

Slope =−6/5

Y-Intercept =2

Answer 1

The point-slope form of a linear equation is given by y - y₁ = m(x - x₁), where (x₁, y₁) represents a point on the line, and m represents the slope.

Given that the slope (m) is -6/5 and the y-intercept is 2, we can plug in these values into the point-slope form:

y - 2 = (-6/5)(x - 0)

Simplifying further:

y - 2 = (-6/5)x

Thus, the equation of the line in point-slope form is y - 2 = (-6/5)x.

Answer 2

The slope-intercept equation would be y = -(6/5)x + 2 (y = mx + b)

The format for the point-slope form is y - y₁ = m(x - x₁)

There are an infinite number of points that satisfy the slope-intercept equation. As your question doesn't specify a target point, I suggest that you pick an x value, solve for y in 1st equation and use that ordered pair for those x and y values in the point-slope form.

Ex: if x = 5, y = -(6/5)(5) + 2 → y = -6 + 2 = -4, so the ordered pair is (5,-4)

The point-slope format would be y + 4 = -6/5(x - 5)