written in standard and slope intercept form

Question

what is the line (2,-3) and (1,-1) written in standard and slope intercept form

Answer 1

First we need to find the slope: ^rise/_run, or y₂ - y₁ / x₂ - x₁

(-1 - -3) / (1 - 2)

2/-1 --> -2

 

Next we use the point-slope formula to get the basis of our equation. Which point we use does not matter:

y - y₁ = m(x - x₁)

y - -1 = -2(x - 1)

y + 1= -2x + 2

y = -2x + 1

 

That is our slope form. standard form would be to move the variables to one side:

2x + y = 1