Peter R. answered 05/22/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Better to use substitution:
a = 72 - 12s
13(72 - 12s) + 6s = 186
936 - 156s + 6s = 186
-150s = -750
s = $5.00. Etc.
Landon W.
asked 05/22/23The school that stefan goes to is selling tickets to a spring musical. On the first day of ticket sales the school sold 1 adult ticket and 12 student tickets for a total of $72. The school took in $186 on the second day by selling 13 adult tickets and 6 student tickets. Find the price of an adult ticket and the price of a student ticket.
Peter R. answered 05/22/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Better to use substitution:
a = 72 - 12s
13(72 - 12s) + 6s = 186
936 - 156s + 6s = 186
-150s = -750
s = $5.00. Etc.
AJ L. answered 05/22/23
Patient and knowledgeable Algebra Tutor committed to student mastery
Make a system of equations
a+12s = 72
13a+6s = 186
By doubling the second equation, we can eliminate the variable "s" to solve for "a":
a+12s = 72
26a+12s = 372
-25a = -300
a = 12 <-- So, 1 adult ticket costs $12
a+12s = 72 <-- Plug a=12 back into first equation to find "s"
12+12s = 72
12s = 60
s = 5 <-- Therefore, 1 student ticket costs $5
The price of an adult ticket is $12 and the price of a student ticket is $5
Hope this helped!
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