Alexander P. answered 05/16/23
Experienced Tutor in High School and College Level Mathematics
First, we must find a general pattern for this sequence. Looking at the first few, we can see that each term is four more than the previous one.
If we let a_i denote the i-th term in the sequence, then
a_1 = -36
a_2 = a_1 + 4 = a_1 + 4*1 = -32
a_3 = a_2 + 4 = (a_1 + 4) + 4 = a_1 + 4*2 = -28
a_4 = a_3 + 4 = (a_1 + 2(4)) + 4 = a_1 + 4*3 = -24
And so on. From this, we can see the pattern. In general, we see that
a_i = a_1 + 4*(i-1) = -36 + 4*(i-1)
Therefore, the 29th term in the sequence is
a_{29} = -36 + 4*(29-1) = -36 + 4*28 = -36 + 112 = 76.