Divide this problem

Question

Answer 1

a³+c³ = (a+c)(a²+ac+c²), so (a+c)(a²+ac+c²)/(a+c) = a²+ac+c²

Hope this helped!

Answer 2

You should learn formula a³ + b³ = (a + b)(a² - ab + b² ) (proof is on the web at https://byjus.com/maths/a-cube-b-cube-formula/)

So here (a³ + c³)/(a + c) = (a + c)(a² - ac + c²)/(a + c) So the (a + c) terms cancel,

leaving a² - ac + c²