Peter R. answered 04/11/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Looks like it's linear. Chg in temp/time req'd has the same value in each time period.
You could plot the points with temp on the y-axis and time across the x-axis.
(1900 - 1950)/ (20 - 15) = -50/5 = -10 degrees F/min.
(1800 - 1900)/(30 - 20) = -100/10 = -10 " "
(1500 - 1800)/(60 - 30) = -300/30 = -10 " "
Overall, the temp dropped 450 degrees in 45 minutes, or 10 degrees/min.
So the slope is -10 degrees/min. (m in the slope-intercept linear formula)
y = mx + b or, in this case temp = m(time) + b. Need to find b by plugging in any pair of values:
1500 = -10(60) + b -> b = 1500 + 600 = 2100 degrees
(a) T(t) = -10t + 2100
(b) Is pretty self-explanatory.
(c) Can you substitute the appropriate value for 3 hrs for t in the equation? (Remember, t is defined in minutes)