Raymond B. answered 03/31/23
Math, microeconomics or criminal justice
x+4=0
x-6=0
(x+4)(x-6)=0
x^2-2x -24=0
x=2+3i
x-2=3i
x^2-4x +4= -9
x^2 -4x +13=0
(f(x)= (x^2-4x +13)(x^2-2x-24)=0
f(x)= x^4 -6x^3 -19x^2 +70x - 372
May B.
asked 03/31/23Find an nth-degree polynomial function with real coefficient of 1, and satisfying the given conditions.
n =4; -4, 6, and 2 + 3i are zeros
f(x)=
Raymond B. answered 03/31/23
Math, microeconomics or criminal justice
x+4=0
x-6=0
(x+4)(x-6)=0
x^2-2x -24=0
x=2+3i
x-2=3i
x^2-4x +4= -9
x^2 -4x +13=0
(f(x)= (x^2-4x +13)(x^2-2x-24)=0
f(x)= x^4 -6x^3 -19x^2 +70x - 372
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