assume that y varies inversely with c. if y=4 when x=4 find y when x=2

Answer 1

Since y varies inversely with c, we can write:

y = k/c

where k is a constant of proportionality.

We can find the value of k using the given information that y=4 when x=4:

4 = k/4

k = 16

Now we can use the equation y = 16/c to find y when x=2:

y = 16/c

Since we don't know the value of c, we can't directly substitute x=2 into this equation. However, we can use the fact that the relationship between y and c is inverse to write:

y1 * c1 = y2 * c2

where y1 and c1 are the initial values of y and c (y=4 and x=4), and y2 and c2 are the final values we want to find (y when x=2 and c is unknown).

Substituting the given values, we get:

4 * 4 = y2 * c2

Simplifying, we get:

y2 = 16/c2

Now we can use the fact that x=2 to write:

y1 * c1 = y2 * c2

Substituting the known values, we get:

4 * 4 = y2 * c2

Solving for y2, we get:

y2 = 16/2 = 8

Therefore, when x=2, y is equal to 8.

Answer 2

y varies inversely with x

y = k/x

4 =k/4

k =16

y = 16/x

when x =2

y = 16/2 = 8

y = 8