Dalton R.

asked • 03/28/23

if f(1)=4 and f(n)=f(n-1)^2+5 then find the value of f(3)

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Robert K. answered • 03/28/23

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f(1) = 4


f(2) = 4^2 + 5 = 21


f(3)= 21^2 + 5 = 446

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David W.

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If f(n) is the function listed, f(1) = 5, so something is off.
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04/01/23

Robert K.

I'm sorry but I don't understand your comment. I went with what was given i.e. f(1) = 4 and then used the recursive rule twice to find f(3).
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04/01/23

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