algebra question! urgent and need asap!

Question

write the quadratic equation whose roots are 6 and 5, and whose leading coefficient is 4

Answer 1

4(x-6)(x-5) = 0

If you like you can multiply out the parentheses.

Answer 2

A quadratic equation is in the form of ax² + bx + c = 0. Since we need a quadratic equation with roots of 6 and 5 and a leading coefficient of 4, we will need something like the following n(x - a)(x - b) = 0, where n is the leading coefficient, and a and b are the roots. When plugging these wanted values in, we get 4(x - 6)(x - 5) = 0. When multiplying this out, we will get the quadratic equation:

(4x - 24)(x - 5) = 0

4x² - 20x - 24x + 120 = 0

4x² - 44x + 120 = 0