Peter R. answered 02/27/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
√-16 = (√16)(√-1) = 4i
(√-3)(√-3) = -3
√(-4)(√-4) = -4
3i2 = 3(√-1)(√-1) = 3(-1) = -3
3i3 = 3(-1)i = -3i
Putting it all together:
4i - (-3) - (-4) + 3i - (-3) + (- 3i)
4i + 3 + 4 + 3i + 3 - 3i
10 + 4i