A trapezoid has an area of 20 cm2 and a height z cm. The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm. Find the height, z

Answer 1

(4z+1)z=20

4z^2 +z -20 = 0

z= -1/8 +(1/8)sqr321

z= about 2.11 cm

parallel sides are 2z+3 = 4.22+3 = 7.22

and 6z-1 = 12.66-1 =11.66

Area = about 2.11(11.66+7.22)/2

= 2.11(18.88)/2

= 2.11(9.44)

= about 20