Raymond B. answered 02/21/23
Math, microeconomics or criminal justice
900 km covered in 3 hours
900/3 = average 300 km/hr
300/2 = 150 km/h average for the 2 trains
14 difference, add and subtract 14/2 = 7
from 150, to get 157 km/hr and 143 km/hr
or let x+14 = faster train's speed
and x = slower train's speed
multiply by 3 to get their distance in 3 hours
(x+14)3 +3x
=3x +42 +3x
=6x +42 = 900
6x = 900-42 = 858
x = 858/6 = 143 km/hr
x+14 = 157 km/hr
in 3 hours the slower goes 3 times 143= 429
faster goes in 3 hours 3 x 157= 471
471+429=900