Distance Problem

Question

Mya is 96 miles away from Margaret. They are traveling towards each other. If Margaret travels 6 mph faster than Mya and they meet after 6 hours, how fast was each traveling?

Answer 1

Distance = rate x time.

They both travel for 6 hrs before meeting somewhere within the 96 mile distance.

Say Mya travels at x mph, then Margaret would be 6 mph faster, or x + 6 mph.

Mya's distance + Margaret's distance = 96 mi.

so 6x + 6(x + 6) = 96

6x + 6x + 36 = 96

12x = 60 and x = 5 mph (Mya)

Margaret is x + 6 = 5 + 6 = 11mph.

Check: 5(6) + 11(6) = 30 + 66 = 96 mi.